Simple Mayan math
The Mayans had a incredibly sophisticated quantity system. The device was used and developed in hopes of astrological uses. It was a base 20 program, believed to be based on ancient individuals counting on the two their fingertips and their feet, called the vigesimal system. Today we use a bottom 10 program, the decimal system, meaning each place value is usually equal to a power of 12, and in the vigesimal program each place value is usually equal to a power of 20. They also employed separate lots of consisting of lines, dots, and shells. Here are the figures 1 through 29.
Instead of doing work from remaining to correct like our bodies it works levels. The 1st level getting 1, the other level being 20, another 400, your fourth 8000 and so forth. The initial level provides the number zero – 19. On this level one dot is equal to one and one club is equal to 5 and so or model 13 can be two bars (two sets of 5) and three dots (3 units) it can simply a few + a few +3 sama dengan 13. Once it gets to 20, instead of being 5 bars is actually replaced by simply one department of transportation and relocated to the second level. So one example is 26 can be written with one dot in the twenties place and one pub and 1 dot (6) in the ones place. Once comfortable with this concept Mayan addition and subtraction are convenient. If you wanted to add 83 and 59 in Mayan numerals it will look something like this: A more complicated problem just like 478 & 9534 would look like this: Subtraction is performed the exact same method as addition.
Multiplication however , was done in another way. It consisted of drawing lines that correspond to the number the counting the number of crossings in every corner. It absolutely was very simple and simple to do. Say you had been multiplying doze and eleven you would pull one line for the tens place in the 12 and two intended for the ones put in place the 12
and then single line for the tens host to the 11 and a single for the ones place. Count number the number of traversing in the still left corner and the number of traversing in the right corner. In that case add up the number of crossings inside the bottom...